Acid Based Titration Problems 2

0

Acid Based Titration Problems 2

1 / 10

By titration, it was found that an average titre of 9.90cm3 of 1.00 mol dm-3 solution of potassium carbonate was required to just neutralise a 25.00 cm3 sample of sulfuric acid solution. Calculate the concentraion of the sulfuric acid solution.

The equation for the reaction is

K2CO3(aq)+H2SO4(aq)=>K2SO4(aq)+H2O(aq)+CO2(g)

2 / 10

By titration, it was found that an average titre of 19.95cm3 of 0.180 mol dm-3 solution of nitric acid was required to just neutralise a 10.00 cm3 sample of sodium carbonate solution. Calculate the concentraion of the sodium carbonate solution.

The equation for the reaction is

2HNO3(aq)+Na2CO3(aq)=>2NaNO3(aq)+H2O(aq)+CO2(g)

3 / 10

By titration, it was found that an average titre of 28.05cm3 of 0.100 mol dm-3 solution of potassium hydroxide was required to just neutralise a 25.00 cm3 sample of phosphoric acid solution. Calculate the concentraion of the phosphoric acid solution.

The equation for the reaction is

3KOH(aq)+H3PO4(aq)=>K3PO4(aq)+3H2O(aq)

4 / 10

By titration, it was found that an average titre of 21.25cm3 of 2.450 mol dm-3 solution of sulfuric acid was required to just neutralise a 10.00 cm3 sample of barium hydroxide solution. Calculate the concentraion of the barium hydroxide solution.

The equation for the reaction is

H2SO4(aq)+Ba(OH)2(aq)=>BaSO4(aq)+2H2O(aq)

5 / 10

By titration, it was found that an average titre of 31.40cm3 of 0.200 mol dm-3 solution of hydrochloric acid was required to just neutralise a 25.00 cm3 sample of barium hydroxide solution. Calculate the concentraion of the barium hydroxide solution.

The equation for the reaction is

Ba(OH)2(aq)+2HCl(aq)=>BaCl2(aq)+2H2O(aq)

6 / 10

By titration, it was found that an average titre of 21.30cm3 of 0.100 mol dm-3 solution of sulfuric acid was required to just neutralise a 25.00 cm3 sample of potassium hydroxide solution. Calculate the concentraion of the potassium hydroxide solution.

The equation for the reaction is

2KOH(aq)+H2SO4(aq)=>K2SO4(aq)+H2O(aq)

7 / 10

By titration, it was found that an average titre of 16.25cm3 of 0.500 mol dm-3 solution of sulfuric acid was required to just neutralise a 10.00 cm3 sample of sodium hydroxide solution. Calculate the concentraion of the sodium hydroxide solution.

The equation for the reaction is

2NaOH(aq)+H2SO4(aq)=>Na2SO4(aq)+H2O(aq)

8 / 10

By titration, it was found that an average titre of 19.75cm3 of 0.200 mol dm-3 solution of hydrochloric acid was required to just neutralise a 10.00 cm3 sample of lithium hydroxide solution. Calculate the concentraion of the lithium hydroxide solution.

The equation for the reaction is

LiOH(aq)+HCl(aq)=>LiCl(aq)+H2O(aq)

9 / 10

By titration, it was found that an average titre of 25.00cm3 of 1.75 mol dm-3 solution of nitric acid was required to just neutralise a 50.00 cm3 sample of potassium hydroxide solution. Calculate the concentraion of the potassium hydroxide solution.

The equation for the reaction is

KOH(aq)+HNO3(aq)=>KNO3(aq)+H2O(aq)

10 / 10

By titration, it was found that an average titre of 20.00cm3 of 0.150 mol dm-3 solution of hydrochloric acid was required to just neutralise a 10.00 cm3 sample of sodium hydroxide solution. Calculate the concentraion of the sodium hydroxide solution.

The equation for the reaction is

NaOH(aq)+HCl(aq)=>NaCl(aq)+H2O(aq)

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Acid Based Titration Problems 1

43

Acid Based Titration Problems 1

1 / 10

By titration, it was found that an average titre of 28.80cm3 of 2.00 mol dm-3 solution of potassium carbonate was required to just neutralise a 50.00 cm3 sample of sulfuric acid solution. Calculate the concentraion of the sulfuric acid solution.

The equation for the reaction is

K2CO3(aq)+H2SO4(aq)=>K2SO4(aq)+H2O(aq)+CO2(g)

2 / 10

By titration, it was found that an average titre of 22.85cm3 of 0.300 mol dm-3 solution of nitric acid was required to just neutralise a 25.00 cm3 sample of sodium carbonate solution. Calculate the concentraion of the sodium carbonate solution.

The equation for the reaction is

2HNO3(aq)+Na2CO3(aq)=>2NaNO3(aq)+H2O(aq)+CO2(g)

3 / 10

By titration, it was found that an average titre of 21.85cm3 of 0.200 mol dm-3 solution of potassium hydroxide was required to just neutralise a 10.00 cm3 sample of phosphoric acid solution. Calculate the concentraion of the phosphoric acid solution.

The equation for the reaction is

3KOH(aq)+H3PO4(aq)=>K3PO4(aq)+3H2O(aq)

4 / 10

By titration, it was found that an average titre of 26.25cm3 of 1.100 mol dm-3 solution of sulfuric acid was required to just neutralise a 25.00 cm3 sample of barium hydroxide solution. Calculate the concentraion of the barium hydroxide solution.

The equation for the reaction is

H2SO4(aq)+Ba(OH)2(aq)=>BaSO4(aq)+2H2O(aq)

5 / 10

By titration, it was found that an average titre of 45.25cm3 of 0.100 mol dm-3 solution of hydrochloric acid was required to just neutralise a 20.00 cm3 sample of barium hydroxide solution. Calculate the concentraion of the barium hydroxide solution.

The equation for the reaction is

Ba(OH)2(aq)+2HCl(aq)=>BaCl2(aq)+2H2O(aq)

6 / 10

By titration, it was found that an average titre of 19.10cm3 of 0.250 mol dm-3 solution of sulfuric acid was required to just neutralise a 10.00 cm3 sample of potassium hydroxide solution. Calculate the concentraion of the potassium hydroxide solution.

The equation for the reaction is

2KOH(aq)+H2SO4(aq)=>K2SO4(aq)+H2O(aq)

7 / 10

By titration, it was found that an average titre of 23.45cm3 of 0.100 mol dm-3 solution of sulfuric acid was required to just neutralise a 25.00 cm3 sample of sodium hydroxide solution. Calculate the concentraion of the sodium hydroxide solution.

The equation for the reaction is

2NaOH(aq)+H2SO4(aq)=>Na2SO4(aq)+H2O(aq)

8 / 10

By titration, it was found that an average titre of 22.25cm3 of 0.100 mol dm-3 solution of hydrochloric acid was required to just neutralise a 20.00 cm3 sample of lithium hydroxide solution. Calculate the concentraion of the lithium hydroxide solution.

The equation for the reaction is

LiOH(aq)+HCl(aq)=>LiCl(aq)+H2O(aq)

 

9 / 10

By titration, it was found that an average titre of 20.00cm3 of 1.20 mol dm-3 solution of nitric acid was required to just neutralise a 25.00 cm3 sample of potassium hydroxide solution. Calculate the concentraion of the potassium hydroxide solution.

The equation for the reaction is

KOH(aq)+HNO3(aq)=>KNO3(aq)+H2O(aq)

 

10 / 10

By titration, it was found that an average titre of 25.00cm3 of 0.100 mol dm-3 solution of hydrochlorc acid was required to just neutralise a 25.00 cm3 sample of sodium hydroxide solution. Calculate the concentraion of the sodium hydroxide solution.

The equation for the reaction is

NaOH(aq)+HCl(aq)=>NaCl(aq)+H2O(aq)

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Dilution Calculations

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Dilution Calculations

1 / 10

If you were asked to prepare 104cm3 of 0.389 mol dm-3 ethanoic acid from 0.800 mol dm-3, what volume (in cm3) of ethanoic acid would you need to dilute with deionised water to achieve a total volume of 104cm3 of diluted solution?

2 / 10

If you were asked to prepare 103cm3 of 0.245 mol dm-3 ammonia solution from 1.27 mol dm-3, what volume (in cm3) of ammonia solution would you need to dilute with deionised water to achieve a total volume of 103cm3 of diluted solution?

3 / 10

If you were asked to prepare 400cm3 of 0.100 mol dm-3 sulfuric acid from 1.00 mol dm-3, what volume (in cm3) of sulfuric acid would you need to dilute with deionised water to achieve a total volume of 400cm3 of diluted solution?

4 / 10

If you were asked to prepare 500cm3 of 0.500 mol dm-3 nitric acid from 2.00 mol dm-3, what volume (in cm3) of nitric acid would you need to dilute with deionised water to achieve a total volume of 500cm3 of diluted solution?

5 / 10

If you were asked to prepare 100cm3 of 1.00 mol dm-3 hydrochloric acid from 2.00 mol dm-3, what volume (in cm3) of hydrochloric acid would you need to dilute with deionised water to achieve a total volume of 100cm3 of diluted solution?

6 / 10

What volume (in cm3) of deionised water would you need to add to 60.0cm3 of ethanoic acid to dilute it from a concentration of 0.200 mol dm-3 into a concentration of 0.180 mol dm-3?

7 / 10

What volume (in cm3) of deionised water would you need to add to 50.0cm3 of ammonia solution to dilute it from a concentration of 10.0 mol dm-3 into a concentration of 1.00 mol dm-3?

8 / 10

What volume (in cm3) of deionised water would you need to add to 80.0cm3 of sulfuric acid to dilute it from a concentration of 0.500 mol dm-3 into a concentration of 0.400 mol dm-3?

9 / 10

What volume (in cm3) of deionised water would you need to add to 200cm3 of nitric acid to dilute it from a concentration of 4.00 mol dm-3 into a concentration of 1.00 mol dm-3?

10 / 10

What volume (in cm3) of deionised water would you need to add to 100cm3 of hydrochloric acid to dilute it from a concentration of 2.00 mol dm-3 into a concentration of 1.00 mol dm-3?

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Concentration from Mass & Volume 6

1

Concentration from Mass & Volume 6

1 / 10

Calculate the concentration of HCl in a solution of volume 1.25dm3 that contains 460 g of HCl

H=1 Cl=35.5

2 / 10

Calculate the concentration of FeSO4 . 7H2O in a solution of volume 1.92dm3 that contains 380 g of FeSO4 . 7H2O

S=32.1 Fe=55.8 O=16.0 H=1.0

3 / 10

Calculate the concentration of Al2(SO4)3 in a solution of volume 2.26dm3 that contains 500 g of Al2(SO4)3

S=32.1 Al=27.0 O=16.0

4 / 10

Calculate the concentration of KHCO3 in a solution of volume 0.75dm3 that contains 200 g of KHCO3

K=39.1 H=1.0 C=12.0 O=16.0

5 / 10

Calculate the concentration of NH4NO3 in a solution of volume 1.40dm3 that contains 50.0 g of NH4NO3

N=14.0 O=16.0 H=1.0

6 / 10

Calculate the concentration of Ba(NO3)2 in a solution of volume 1100.00cm3 that contains 76.0 g of Ba(NO3)2

Ba=137.3 N=14.0 O=16.0

7 / 10

Calculate the concentration of NH3 in a solution of volume 800.00cm3 that contains 100 g of NH3

N=14.0 H=1.0

8 / 10

Calculate the concentration of NaOH in a solution of volume 22.50cm3 that contains 160 g of NaOH

Na=23.0 O=16.0 H=1.0

9 / 10

Calculate the concentration of CuSO4 in a solution of volume 750.00cm3 that contains 170 g of CuSO4

S=32.1 Cu=63.5.0 O=16.0

10 / 10

Calculate the concentration of C12H22O11 in a solution of volume 33.00cm3 that contains 6.80 g of C12H22O11

H=1.0 C=12.0 O=16.0

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Concentration from Mass & Volume 5

0

Concentration from Mass & Volume 5

1 / 10

Calculate the concentration of sodium chloride in a solution of volume 1.25dm3 that contains 89.0 g of sodium chloride

Na=23.0 Cl=35.5

2 / 10

Calculate the concentration of lithium hydroxide in a solution of volume 2.20dm3 that contains 89.0 g of lithium hydroxide

Li=6.9 O=16.0 H=1.0

3 / 10

Calculate the concentration of iodine in a solution of volume 4.80dm3 that contains 250 g of iodine

I=126.9

4 / 10

Calculate the concentration of sodium hydroxide in a solution of volume 1.25dm3 that contains 30.0 g of sodium hydroxide

Na=23.0 O=16.0 H=1.0

5 / 10

Calculate the concentration of glucose in a solution of volume 1.50dm3 that contains 600 g of glucose

H=1.0 C=12.0 O=16.0

6 / 10

Calculate the concentration of ammonium nitrate in a solution of volume 1500cm3 that contains 56.0 g of ammonium nitrate

N=14.0 O=16.0 H=1.0

7 / 10

Calculate the concentration of potassium hydrogencarbonate in a solution of volume 425cm3 that contains 75.0 g of potassium hydrogencarbonate

K=39.1 H=1.0 C=12.0 O=16.0

8 / 10

Calculate the concentration of barium nitrate in a solution of volume 19.85cm3 that contains 4.82 g of barium nitrate

Ba=137.3 N=14.0 O=16.0

9 / 10

Calculate the concentration of aluminium sulfate in a solution of volume 250.00cm3 that contains 4.00 g of aluminium sulfate

S=32.1 Al=27.0 O=16.0

10 / 10

Calculate the concentration of copper (II) sulfate in a solution of volume 21.45cm3 that contains 0.750 g of copper (II) sulfate

S=32.1 Cu=63.5.0 O=16.0

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Concentration from Mass & Volume 4

0

Concentration from Mass & Volume 4

1 / 10

Calculate the concentration of HCl in a solution of volume 2.70dm3 that contains 590 g of HCl

H=1 Cl=35.5

2 / 10

Calculate the concentration of FeSO4 . 7H2O in a solution of volume 2.40dm3 that contains 380 g of FeSO4 . 7H2O

S=32.1 Fe=55.8 O=16.0 H=1.0

3 / 10

Calculate the concentration of Al2(SO4)3 in a solution of volume 4.80dm3 that contains 250 g of Al2(SO4)3

S=32.1 Al=27.0 O=16.0

 

4 / 10

Calculate the concentration of KHCO3 in a solution of volume 0.307dm3 that contains 200 g of KHCO3

K=39.1 H=1.0 C=12.0 O=16.0

5 / 10

Calculate the concentration of NH4NO3 in a solution of volume 0.724dm3 that contains 50.0 g of NH4NO3

N=14.0 O=16.0 H=1.0

6 / 10

Calculate the concentration of Ba(NO3)2 in a solution of volume 1350cm3 that contains 76.0 g of Ba(NO3)2

Ba=137.3 N=14.0 O=16.0

7 / 10

Calculate the concentration of NH3 in a solution of volume 900cm3 that contains 100 g of NH3

N=14.0 H=1.0

8 / 10

Calculate the concentration of NaOH in a solution of volume 22.50cm3 that contains 1.30 g of NaOH

Na=23.0 O=16.0 H=1.0

9 / 10

Calculate the concentration of CuSO4 in a solution of volume 250.00cm3 that contains 20.0 g of CuSO4

S=32.1 Cu=63.5.0 O=16.0

 

10 / 10

Calculate the concentration of C12H22O11 in a solution of volume 33.00cm3 that contains 7.20 g of C12H22O11

H=1.0 C=12.0 O=16.0

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Concentration from Mass & Volume 3

0

Concentration from Mass & Volume 3

1 / 10

Calculate the concentration of sodium chloride in a solution of volume 3.00dm3 that contains 58.5 g of sodium chloride

Na=23.0 Cl=35.5

2 / 10

Calculate the concentration of lithium hydroxide in a solution of volume 1.05dm3 that contains 65.0 g of lithium hydroxide

Li=6.9 O=16.0 H=1.0

3 / 10

Calculate the concentration of iodine in a solution of volume 2.40dm3 that contains 100 g of iodine

I=126.9

4 / 10

Calculate the concentration of sodium hydroxide in a solution of volume 0.375dm3 that contains 30.0 g of sodium hydroxide

Na=23.0 O=16.0 H=1.0

5 / 10

Calculate the concentration of glucose in a solution of volume 2.00dm3 that contains 500 g of glucose

H=1.0 C=12.0 O=16.0

6 / 10

Calculate the concentration of ammonium nitrate in a solution of volume 800cm3 that contains 28.0 g of ammonium nitrate

N=14.0 O=16.0 H=1.0

7 / 10

Calculate the concentration of potassium hydrogencarbonate in a solution of volume 280cm3 that contains 50.0 g of potassium hydrogencarbonate

K=39.1 H=1.0 C=12.0 O=16.0

8 / 10

Calculate the concentration of barium nitrate in a solution of volume 21.95cm3 that contains 0.670 g of barium nitrate

Ba=137.3 N=14.0 O=16.0

9 / 10

Calculate the concentration of aluminium sulfate in a solution of volume 190.00cm3 that contains 5.00 g of aluminium sulfate

S=32.1 Al=27.0 O=16.0

10 / 10

Calculate the concentration of copper (II) sulfate in a solution of volume 23.00cm3 that contains 1.04 g of copper (II) sulfate

S=32.1 Cu=63.5.0 O=16.0

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Concentration from Mass & Volume 2

0

Concentration from Mass & Volume 2

1 / 10

Calculate the concentration of HCl in a solution of volume 1.25dm3 that contains 640 g of HCl

H=1 Cl=35.5

2 / 10

Calculate the concentration of FeSO4 . 7H2O in a solution of volume 2.40dm3 that contains 380 g of FeSO4 . 7H2O

S=32.1 Fe=55.8 O=16.0 H=1.0

3 / 10

Calculate the concentration of Al2(SO4)3 in a solution of volume 4.80dm3 that contains 400 g of Al2(SO4)3

S=32.1 Al=27.0 O=16.0

4 / 10

Calculate the concentration of KHCO3 in a solution of volume 0.75dm3 that contains 200 g of KHCO3

K=39.1 H=1.0 C=12.0 O=16.0

5 / 10

Calculate the concentration of NH4NO3 in a solution of volume 1.40dm3 that contains 50.0 g of NH4NO3

N=14.0 O=16.0 H=1.0

6 / 10

Calculate the concentration of Ba(NO3)2 in a solution of volume 1400cm3 that contains 76.0 g of Ba(NO3)2

Ba=137.3 N=14.0 O=16.0

7 / 10

Calculate the concentration of NH3 in a solution of volume 800cm3 that contains 100 g of NH3

N=14.0 H=1.0

8 / 10

Calculate the concentration of NaOH in a solution of volume 22.50cm3 that contains 1.50 g of NaOH

Na=23.0 O=16.0 H=1.0

9 / 10

Calculate the concentration of CuSO4 in a solution of volume 250.00cm3 that contains 20.0 g of CuSO4

S=32.1 Cu=63.5.0 O=16.0

10 / 10

Calculate the concentration of C12H22O11 in a solution of volume 33.00cm3 that contains 7.20 g of C12H22O11

H=1.0 C=12.0 O=16.0

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Concentration from Mass & Volume 1

0

Concentration from Mass & Volume 1

1 / 10

Calculate the concentration of sodium chloride in a solution of volume 4.25dm3 that contains 58.5 g of sodium chloride

Na=23.0 Cl=35.5

2 / 10

Calculate the concentration of iodine in a solution of volume 1.20dm3 that contains 100 g of iodine

I=126.9

3 / 10

Calculate the concentration of sodium hydroxide in a solution of volume 0.75dm3 that contains 30.0 g of sodium hydroxide

Na=23.0 O=16.0 H=1.0

4 / 10

Calculate the concentration of glucose in a solution of volume 1.50dm3 that contains 500 g of glucose

H=1.0 C=12.0 O=16.0

5 / 10

Calculate the concentration of ammonium nitrate in a solution of volume 1500cm3 that contains 28.0 g of ammonium nitrate

N=14.0 O=16.0 H=1.0

6 / 10

Calculate the concentration of potassium hydrogencarbonate in a solution of volume 900cm3 that contains 50.0 g of potassium hydrogencarbonate

K=39.1 H=1.0 C=12.0 O=16.0

7 / 10

Calculate the concentration of barium nitrate in a solution of volume 22.50cm3 that contains 0.670 g of barium nitrate

Ba=137.3 N=14.0 O=16.0

8 / 10

Calculate the concentration of aluminium sulfate in a solution of volume 250.00cm3 that contains 5.00 g of aluminium sulfate

S=32.1 Al=27.0 O=16.0

9 / 10

Calculate the concentration of copper (II) sulfate in a solution of volume 33.00cm3 that contains 1.04 g of copper (II) sulfate

S=32.1 Cu=63.5.0 O=16.0

10 / 10

Calculate the concentration of lithium hydroxide in a solution of volume 2.20dm3 that contains 65.0 g of lithium hydroxide

Li=6.9 O=16.0 H=1.0

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Volumes from Concentrations & Moles 3

0

Volumes from Concentrations & Moles 3

1 / 10

Calculate the volume of solution in cm3 that would contain 0.200 mol of lithium iodide if the concentration of the solution is 0.800 mol cm-3

2 / 10

Calculate the volume of solution in cm3 that would contain 0.200 mol of hydrochloric acid if the concentration of the solution is 0.900 mol cm-3

3 / 10

Calculate the volume of solution in cm3 that would contain 5.00 mol of glucose if the concentration of the solution is 2.50 mol cm-3

4 / 10

Calculate the volume of solution in cm3 that would contain 0.080 mol of iron (II) nitrate if the concentration of the solution is 0.225 mol cm-3

5 / 10

Calculate the volume of solution in cm3 that would contain 0.500 mol of H+ ions if the concentration of the solution is 0.500 mol cm-3

6 / 10

Calculate the volume of solution in dm3 that would contain 0.0100 mol of manganate (VII) ions if the concentration of the solution is 0.0800 mol dm-3

7 / 10

Calculate the volume of solution in dm3 that would contain 0.150 mol of chlorate (I) ions if the concentration of the solution is 0.300 mol dm-3

8 / 10

Calculate the volume of solution in dm3 that would contain 0.00600 mol of KCN if the concentration of the solution is 0.00500 mol dm-3

9 / 10

Calculate the volume of solution in dm3 that would contain 0.300 mol of NO3- ions if the concentration of the solution is 1.30 mol dm-3

10 / 10

Calculate the volume of solution in dm3 that would contain 0.450 mol of Ag+ ions if the concentration of the solution is 0.500 mol dm-3

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